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Ali-F

How To Solve These With Intermediate Results

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Hey

 

I have these math problems, but I am not really searching for the answers. but rather the intermediate results. 

 

E.g: 2x2 + (2-2)

 

4 + 0

= 0

 

like that. so here it comes:

 

I need to reduce this fraction:

 

5 * 2/3

 

(i cant copy frm word and make it look more nice to look at)

 

: remember i need how to write it down (i.e showing my teacher how i did it)

 

 

2)

 

2/3 - 4/5 + 1/6

 

???

 

 

3: 

 

4 (c-d) - 3 (c + 2d)

 

how do I simplify this?? I mean, i wonder what to do with 4 and -3 ???

 

 

 


Lastly: (a+5b) +2 (2a+ b )

Edited by Ali-F

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I think this is how you do q2

2/3 =20/30 (2x10 and 3x10)

4/5= 24/30(4x6 and 5x6)

1/6= 5/30(1x5 and 6x5)

 

20-24+5 = 1

 

 

and for the last one (a+5b)+2(2a+ b ) = a +5b +  4a+ 2b 

= 5a + 7b

 

also the answer to the first one is not 0, 4 + 0 = 4

Edited by labaikYaZahra

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Hey

 

 

4 (c-d) - 3 (c + 2d)

 

how do I simplify this?? I mean, i wonder what to do with 4 and -3 ???

 

 

 

Lastly: (a+5b) +2 (2a+ b )

 

simplifying 4(c-d) - 3(c+2d) is basically writing it shorter, you have to multiply what is between the paranthesis with the number that stand before them. 

 

so: 4 x (c-d) - 3 x (c+2d) = 

      4c - 4d - 3c + 6d=  

      4c - 3c - 4d +6d= 

      1c + 2d 

 

the last one: (a+5b) + 2(2a + b )=  

                     a+5b + 4a + 2b= 

                     a + 4a + 5b + 2b=

                     5a + 7b

 

Someone correct me if I'm wrong, it has been a long while lol.    

 

lol i just noticed labaikyazahra already gave you the last one 

Edited by Pinata

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For the last 2, remember the distributive property. Then collect common terms.

First one is simple multiplication.

Second one find a common denominator and work from there.

Does this make sense?

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if you think of it as physical then it will make sense 

 

6(3+4) is originally 

 

6 red boxes containing 3 apples = 18

6 blue boxes containing 4 apples = 24

 

total apples = 18 + 24 = 42 apple

 

It is wrong to say :

6 boxes each containing 3 apples then thats 18 apples + 4 boxes = 22 (22 what? boxes or apples?)

 

OR

 

4 red boxes that contain 6 apples 

3 blue boxes that contain 6 apples 

 

7 boxes in total each containing 6 apples 

7x6 = 42

 

 

it is really as simple as rearranging the cubes or making as much as ice-cream flavors possible

 

to make your life simple with math , keep in mind the operations orders 

http://www.mathsisfun.com/operation-order-bodmas.html

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jazzakallahumullah khayr..

 

I appreciate your help, however, I haven't understood how to solve the fractions (with the intermediate results). 

 

 

ws


and, how do i solve this shaytan :

 

- (a + x) (x+y) 

 

it's the  substraction sign who's confussing me

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and lastly, what about this?

 

a (a - b ) + b (a + b ) 

 

--- i got my answer to: a- a2 + b2 + b2

 

can i simplify it any more?

 

(salam) brother

 

One thing I'm sure is that your answer is incorrect. When you do a(a - b ) + b(a + b ), you calculate it like this (step-by-step) -> (a * a - a * b ) + (b * a + b * b ) -> (a^2 - ab) + (ba + b^2) -> a^2 - ab + ba + b^2 -> a^2 + b^2. Notice that ab is same like ba, thus (-ab) + ba = 0.

 

It's very important that you know noteworthiness multiplication, division, plus and minus. Most important and what must always be calculated in theorem is multiplication, then division then minus and plus. Hope this helps. 

Edited by sayedamir2000

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(salam) brother

 

One thing I'm sure is that your answer is incorrect. When you do a(a - b ) + b(a + b ), you calculate it like this (step-by-step) -> (a * a - a * b ) + (b * a + b * b ) -> (a^2 - ab) + (ba + b^2) -> a^2 - ab + ba + b^2 -> a^2 + b^2. Notice that ab is same like ba, thus (-ab) + ba = 0.

 

It's very important that you know noteworthiness multiplication, division, plus and minus. Most important and what must always be calculated in theorem is multiplication, then division then minus and plus. Hope this helps. 

 

 

bro, in this

 

-> (a^2 - ab) + (ba + b^2) 

 

you did not remove the brackets why?

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bro, in this

 

-> (a^2 - ab) + (ba + b^2) 

 

you did not remove the brackets why?

 

(salam) brother

 

No I didn't removed the brackets. That's the clean version from (a * a - a * b ) + (b * a + b * b ). 

a * a = a^2

-a * b = -ab

b * a = ba is same as ab

b * b = b^2

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